Different voltage combinations can be obtained from one three phase delta supply however, by making connections or ‘taps’ along the windings of the supply transformers. About the author, Hi All, Thank you so much! For three phase motor amps calculation, the below formula is used. If the voltage supplied from the grid changes within acceptable tolerances, say 5%, what would you expect will happen to the Power (kW) which I measure?. This can be represented diagrammatically by both waveforms and a vector diagram (Figure 2). Planning to make the new site live in about a week. 3 phase motor current calculation formula is P/(√3xVxPfxEff) or P/(1.732xVxPfxEff) Both are the same. 746/3 = 249 watts per phase Hi Steven, how to get the total KVA of the system if Line AB =642.24amp. three phase power is 36 kW,  single phase power = 36/3 = 12 kW Thank you! to better understand this or gain more insight, you can read the Introduction to Three Phase Electric Power post.

Divide the power consumption in watts by the line voltage multiplied by the power factor to find the amperage. Single- phase loads are connected to one leg of the wye between line and neutral. 3 PHASE AMPERES - 80% POWER FACTOR* (Extended Table).

Copyright © 2020 Multiply Media, LLC. You can find more information on power factor here: http://myelectrical.com/notes/entryid/197/power-factor As a note, it is possible to have a different power factor in each phase of a three phase system. alternating-current-circuits Have a read of the note and if you are still unclear, you can add a comment to post. But in the example I gave you the loads are quite obviously not balanced.

The connection is usually drawn as shown in Figure 7 and is known a delta connection after the shape of the Greek letter delta, Δ. Regards Abdulla. You would have 208 volts across each of the loads you gave and can find the current using Ohm’s law (i.e.

I = 249/(1.73*0.72*380) = 0.52 A Hope this makes sense. phase 1 apparent power = 80 x 230 = 18,400 VA = 18.4 kVA      Similarly for phase B (1/2AB + 1/2BC) and phase C (1/2BC + 1/2AC). Easy enough.

In the post, the motor is a three phase load, where as the socket is single phase - in each case case you have the line current which is common (for example, the current flowing in L1). Sir, when a voltage dip occurs current increases, so instead of dimming, a bulb should glow brighter but the reverse thing happens, why? The wye configuration can also supply single or three phase power to higher power loads at a higher voltage. In this situation and with a little thought it is possible to extend the above type of calculation to unbalanced current three phase systems. If it is star connected than the phase voltage is 240/sqrt(3) = 138 V and the current is 56,000/138 = 400 A. GENERATOR AMP RATINGS - THREE PHASE EXTENDED: 3 PHASE AMPERES - 80% POWER FACTOR* (Extended Table) kW Times 1000 divided by (Volts*1.73) *.80. I've always been bad a remembering formulae, so I prefer to remember concepts/methods. Hi Steven, I drive a centrifugal water pump with a three phase motor. Go back to Three phase power measurements ↑. Kindly I want to know in 3 phase distribution ( example a house), Say I have 29 kVA ... equals to 36,250watts  (PF=0.8). We will hook that to a trio of 208 single phase power distribution units, each attached to one pair of phase leads. = kW / (√3 x pf x VLL) - your formulae 21,000 / 230 = 91 A. When the load current in each phase is the same the load is said to be balanced. On the Star Delta. Each conductor is 1/3 cycle out of phase with the other two. With the load balanced, and the three currents phase shifted by 120° from each other, the sum of the current at any instant is zero and there is no current in the return line. phase 2 apparent power = 70 x 230 = 16,100 VA = 16.1 kVA     
V Line-Line = 380 V Three phase power circuits are often used in power transmission lines and large electric motors because they allow lower line voltages and provide a smoother flow of electricity. Robert, I make the line current as 33.6 A. 345/219 = 1.57 A per Phase = Line If you have some expert knowledge or experience, why not consider sharing this with our community.

I'm not sure of where you are getting your 491.5A from.

In a three phase system, the amount of current going through one of the phases is not a fraction of the amount of current going through all three? Why is the Y and Delta line current the same? Your correct it is the RMS current. Please check this and if you find any errors or mistakes let me know. Alternatively, the three supplies can be connected to a common return, as shown in Figure 4.
Consider three single-phase systems each supplying 100W to a load (Figure 3). What is the timing order of an 1985 Plymouth horizon? My advice would be to always try remember the method and not simply memorize formula.


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